A heating coil of power 500W boils a certain quantity of water (at boiling point) in 25 minutes What is the amount of water present ( specific heat capacity of vaporization of water is 33600J/kg/k
To calculate the amount of water present, we can use the equation:
Power = Energy / Time
First, let's convert the time from minutes to seconds:
25 minutes = 25 * 60 = 1500 seconds
Now, we can rearrange the equation to solve for energy:
Energy = Power * Time
Energy = 500W * 1500s = 750,000 J
The energy required to boil the water is equal to the mass of water multiplied by the specific heat capacity of vaporization of water:
Energy = Mass * Specific heat capacity
750,000 J = Mass * 33,600 J/kg
Now we can solve for the mass of water:
Mass = 750,000 J / (33,600 J/kg) = 22.3214 kg
Therefore, the amount of water present is approximately 22.32 kg.
To find the amount of water present, we can use the formula for power:
Power = energy / time
Rearranging the formula, we can solve for energy:
Energy = Power × time
The energy required to vaporize a certain amount of water is given by:
Energy = mass × specific heat capacity of vaporization
Let's plug in the values we know:
Power = 500W
Time = 25 minutes = 25 × 60 seconds = 1500 seconds
Specific heat capacity of vaporization of water = 33600 J/kg
Now we can solve for the mass of water:
Energy = mass × specific heat capacity of vaporization
mass = Energy / specific heat capacity of vaporization
First, let's calculate the energy:
Energy = Power × time
= 500W × 1500 seconds
= 750000 J
Now we can calculate the mass:
mass = Energy / specific heat capacity of vaporization
= 750000 J / 33600 J/kg
≈ 22.32 kg
Therefore, the amount of water present is approximately 22.32 kg.