A square has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on A squirrel has stored it’s acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to it stored acorns in 5.2 5 seconds interpret the quotient to describe the rate of change in the score is high above the ground give your answer to the nearest, hundred.
The quotient that describes the rate of change in the squirrels height above the ground is -10.48 ft./sec
The quotient that describes the rate of change in the squirrels high above the ground is -19.05 feet/sec.
The quotient that describes the rate of change in the squirrels high above the ground is 10.48 feet/sec.
The quotient that describes the rate of change in the squirrels high above the ground is 19.05 feet/sec.
MULTIPLY AND DIVIDE RATIONAL NUMBERS
The correct answer is "The quotient that describes the rate of change in the squirrel's height above the ground is -10.48 ft./sec."
To find the rate of change, we need to divide the change in height by the change in time.
The squirrel starts on a perch 100 feet above the ground and moves down to its stored acorns in 5.2 seconds.
The change in height is 100 ft (perch height) - 45 ft (acorn hole height) = 55 ft.
The change in time is 5.2 seconds.
To find the rate of change, we divide the change in height by the change in time:
Rate of change = change in height / change in time
Rate of change = 55 ft / 5.2 sec
Simplifying the quotient gives us:
Rate of change = 10.58 ft/sec
Therefore, the quotient that describes the rate of change in the squirrel's height above the ground is 10.58 ft/sec (rounded to the nearest hundredth).