The chemist measures the volume of the unknown liquid as 0.719L and the mass of the unknown liquid as 907 g
Methyl acetate 0.93g/cm^3
Chloroform 1.5g/cm^3
Carbon tetrachloride 1.6g/cm^3
Diethylamine 0.71g/cm^3
Ethanolamine 1.0g/cm^3
Caluculate the density of liquid be sure your answer has the correct number of significant digits in g/cm^3
Given data is it possible to identify the liquid
If it is possible to identify the liquid do so
To calculate the density of the liquid, we can use the formula:
Density = Mass / Volume
Given that the mass of the unknown liquid is 907 g and the volume is 0.719 L, we can substitute these values into the formula:
Density = 907 g / 0.719 L
Density ≈ 1262.12 g/L
To convert the density to g/cm³, we need to divide by 1000 (since there are 1000 cm³ in 1 L):
Density ≈ 1.26212 g/cm³
Now, let's compare this density value to the density values of the given substances:
Methyl acetate: 0.93 g/cm³
Chloroform: 1.5 g/cm³
Carbon tetrachloride: 1.6 g/cm³
Diethylamine: 0.71 g/cm³
Ethanolamine: 1.0 g/cm³
Based on the calculated density of approximately 1.26212 g/cm³, it does not match any of the given substances' densities exactly. Therefore, it is not possible to identify the liquid based solely on the given data.
To calculate the density of the unknown liquid, we can use the formula:
Density = Mass / Volume
Given:
Volume of unknown liquid = 0.719 L
Mass of unknown liquid = 907 g
Density = 907 g / 0.719 L
Let's calculate the density:
Density = 907 g / 0.719 L
Density ≈ 1261.69 g/L
Now, let's check if it's possible to identify the liquid based on its density.
Comparing the calculated density with the densities of the given liquids, we find:
Methyl acetate: 0.93 g/cm^3
Chloroform: 1.5 g/cm^3
Carbon tetrachloride: 1.6 g/cm^3
Diethylamine: 0.71 g/cm^3
Ethanolamine: 1.0 g/cm^3
The closest density to 1261.69 g/L is Chloroform, with a density of 1.5g/cm^3. Therefore, it is possible to identify the liquid as Chloroform.