Bobby is 98/2 inches tall. Catherine is 121/3 inches tall. How many inches taller is Bobby than Catherine
To find the difference in height between Bobby and Catherine, we need to subtract Catherine's height from Bobby's height.
Bobby's height is 98/2 inches.
Catherine's height is 121/3 inches.
To subtract fractions, the denominators must be the same. Let's convert both fractions to have a denominator of 6.
For Bobby's height:
98/2 * 3/3 = (98*3)/(2*3) = 294/6
For Catherine's height:
121/3 * 2/2 = (121*2)/(3*2) = 242/6
Now we can subtract the two heights:
Bobby's height - Catherine's height = 294/6 - 242/6
= (294 - 242)/6 = 52/6 = 8 2/6 inches
Bobby is 8 2/6 inches taller than Catherine.
To find out how many inches taller Bobby is than Catherine, we need to subtract Catherine's height from Bobby's height.
Bobby's height is 98/2 inches, and Catherine's height is 121/3 inches.
To subtract the fractions, we need to find a common denominator first. The least common denominator (LCD) of 2 and 3 is 6.
To make the denominators of both fractions equal to 6, we can multiply the fraction by the appropriate factor.
Bobby's height in sixths can be calculated as (98/2) * (3/3) = (294/6) inches.
Catherine's height in sixths can be calculated as (121/3) * (2/2) = (242/6) inches.
Now, we can subtract Catherine's height from Bobby's height to find the difference.
(294/6) - (242/6) = (52/6) inches.
Therefore, Bobby is 52/6 inches taller than Catherine.