A rental car company charges $48 per day to rent a car and $0.08 for every mile driven. Bilquis wants to rent a car, knowing that:
She plans to drive 175 miles.
She has at most $110 to spend.
Write and solve an inequality which can be used to determine
x, the number of days Bilquis can afford to rent while staying within her budget.
Let x be the number of days Bilquis can afford to rent.
The cost for renting the car per day is $48.
The cost for driving 175 miles is (175 * $0.08) = $14.
The total cost for x days is 48x.
The total cost for driving 175 miles is 14.
The total cost should be less than or equal to $110.
Therefore, the inequality is:
48x + 14 ≤ 110
To solve for x, we can first subtract 14 from both sides of the inequality:
48x ≤ 110 - 14
48x ≤ 96
Then, divide both sides of the inequality by 48:
x ≤ 96/48
x ≤ 2
Therefore, Bilquis can afford to rent the car for a maximum of 2 days while staying within her budget.
Let x be the number of days Bilquis can afford to rent a car.
The cost of renting a car for x days is given by:
48x (for the daily rate) + 0.08 * 175 (for the mileage charge)
The inequality for staying within her budget can be represented as:
48x + 0.08 * 175 ≤ 110
Simplifying this inequality, we have:
48x + 14 ≤ 110
Subtracting 14 from both sides of the inequality:
48x ≤ 110 - 14
48x ≤ 96
Dividing both sides of the inequality by 48:
x ≤ 96 / 48
x ≤ 2
Therefore, Bilquis can afford to rent the car for a maximum of 2 days to stay within her budget.