Jill solves the equation 3(x−5)+2x=0
Fill in the blanks with the correct values:
3x+ Response area +2x=0
5x=Response area
x= Response area
options
1) 5
2) -1
3) -5
4) -15
5) -3
6) 15
7) 1
8) 3
3(x-5) + 2x = 0
Expanding the equation:
3x - 15 + 2x = 0
Combining like terms:
5x - 15 = 0
Adding 15 to both sides:
5x = 15
Dividing both sides by 5:
x = 3
Therefore, the correct values are:
3x + Response area + 2x = 0 (5x)
5x = Response area (15)
x = Response area (3)
The correct answers are:
1) 5
2) -1
3) -5
4) -15
5) -3
6) 15
7) 1
8) 3
The correct responses for each blank are:
1) 5
2) 15
3) 3
To solve the equation 3(x-5) + 2x = 0, we can start by simplifying the equation.
First, distribute the 3 to the terms inside the parentheses:
3x - 15 + 2x = 0
Next, combine like terms by adding the x terms together:
5x - 15 = 0
To isolate the variable x, we can add 15 to both sides of the equation:
5x = 15
Finally, to find the value of x, we divide both sides of the equation by 5:
x = 3
Therefore, the correct values to fill in the blanks are:
3x + 15 + 2x = 0
5x = 15
x = 3
So the correct options to fill in the response areas are:
1) 5
2) -1
3) -5
4) -15
5) -3
6) 15
7) 1
8) 3
The correct answers are:
3x + 15 + 2x = 0 (Response area: 15)
5x = 15 (Response area: 3)
x = 3 (Response area: 3)