Which of the following is an irrational number between 5 and 7: √6, √12, √27, or √36?

An irrational number is a number that cannot be expressed as a simple fraction or as a decimal that terminates or repeats.

√6 ≈ 2.449
√12 ≈ 3.464
√27 ≈ 5.196
√36 = 6

Among the given options, √6 and √12 are irrational numbers. However, only √6 is between 5 and 7.

Show an example of an irrational number between 9 and 11.

√100

√20

√10

√99

Among the given options, √10 is an irrational number between 9 and 11.

√10 ≈ 3.162

Therefore, √10 is an example of an irrational number between 9 and 11.

What is the least integer whose square root is an irrational number between 5 and 7?(1 point)

13

6

26

25

The least integer whose square root is an irrational number between 5 and 7 is 26.

√26 ≈ 5.099

Show an example of a rational number that is between √10 and √11.

3.4

10/3 (10 over 3 fraction)

16/5 (16 over 5 fraction)

3.1

Among the given options, 10/3 is a rational number that is between √10 and √11.

√10 ≈ 3.162
√11 ≈ 3.317

10/3 ≈ 3.333

Therefore, 10/3 is an example of a rational number between √10 and √11.

Which irrational number is between 14−−√ and 18−−√?

√10

√19

√15

√13

To determine which irrational number is between $\sqrt{14}$ and $\sqrt{18}$, we can approximate the square roots:

$\sqrt{14} \approx 3.742$
$\sqrt{18} \approx 4.243$

Among the given options, $\sqrt{15}$ is the only irrational number that falls between these approximations:

$\sqrt{15} \approx 3.873$

Therefore, $\sqrt{15}$ is the irrational number between $\sqrt{14}$ and $\sqrt{18}$.

How many irrational numbers are there between √11 and √17?

four numbers

an infinite number

six numbers

twenty-eight numbers

To determine the number of irrational numbers between $\sqrt{11}$ and $\sqrt{17}$, we need to consider that irrational numbers are infinite in between any two distinct numbers.

$\sqrt{11} \approx 3.317$
$\sqrt{17} \approx 4.123$

Since we have an infinite number of rational numbers between these approximations, the correct answer is that there are an infinite number of irrational numbers between $\sqrt{11}$ and $\sqrt{17}$.

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