In a game 5 points are awarded to each game won and 2 points are deducted for each game lost njoroge attempted 15 games and he had 68 points how many games did he lose
Let's assume that njoroge won x games and lost y games.
Each game won is awarded 5 points, so the total points from winning games is 5x.
Similarly, each game lost deducts 2 points, so the total points lost from losing games is 2y.
We are given that njoroge attempted 15 games, so x + y = 15.
njoroge had a total of 68 points, so 5x - 2y = 68.
To solve for x and y, we can use the system of equations:
x + y = 15
5x - 2y = 68
Multiplying the first equation by 2, we get:
2x + 2y = 30
Adding this equation to the second equation, we have:
2x + 2y + 5x - 2y = 30 + 68
7x = 98
Dividing both sides by 7, we find:
x = 14
Substituting this value of x into the first equation:
14 + y = 15
y = 15 - 14
y = 1
Therefore, njoroge won 14 games and lost 1 game.
To find out how many games Njoroge lost, we need to use the given information.
Let's assume Njoroge won "x" games and lost "y" games.
Since 5 points are awarded for each game won, the total points from the games won will be 5x.
Similarly, since 2 points are deducted for each game lost, the total points deducted from the games lost will be 2y.
According to the information provided, Njoroge attempted 15 games and had 68 points. Therefore, we can create the following equation:
5x - 2y = 68 <-- (Equation 1)
Now, we can also use the fact that Njoroge attempted a total of 15 games:
x + y = 15 <-- (Equation 2)
We have two equations (Equations 1 and 2) to solve simultaneously to find the values of "x" and "y".
To do that, let's rearrange Equation 2 to express "x" in terms of "y".
x = 15 - y
Now substitute the value of "x" in Equation 1:
5(15 - y) - 2y = 68
75 - 5y - 2y = 68
Combine like terms:
75 - 7y = 68
Rearrange the equation:
-7y = 68 - 75
-7y = -7
Divide by -7:
y = 1
So, Njoroge lost 1 game.