An insertion mutation occurs, leaving 31 nucleotides in a DNA sequence.
What is the maximum number of codons that could be produced by this sequence?
Choose 1 answer:
Choose 1 answer:
(Choice A) 10
A
10
(Choice B) 31
B
31
(Choice C) 11
C
11
(Choice D) 15
D
15
The maximum number of codons that could be produced by a DNA sequence is determined by the number of nucleotides divided by 3. In this case, there are 31 nucleotides, so the maximum number of codons would be 31/3 = 10. Therefore, the correct answer is (Choice A) 10.
To determine the maximum number of codons that could be produced by a DNA sequence, we need to divide the number of nucleotides by 3 since each codon consists of 3 nucleotides.
In this case, there are 31 nucleotides in the DNA sequence.
When we divide 31 by 3, we get 10 with a remainder of 1.
Therefore, the maximum number of codons that could be produced by this sequence is 10 (Choice A).