Triangle MNO is translated up 5 units and left 2 units. Point N is located at (0, −6). What are the coordinates of N′?(1 point)
To translate a point up 5 units and left 2 units, we subtract 2 from the x-coordinate and add 5 to the y-coordinate.
Since point N is located at (0, -6), the coordinates of N' would be:
x-coordinate: 0 - 2 = -2
y-coordinate: -6 + 5 = -1
Therefore, the coordinates of N' are (-2, -1).
To translate a point up 5 units and left 2 units, we add 5 to the y-coordinate and subtract 2 from the x-coordinate.
Given that the coordinates of point N are (0, -6), we can find the new coordinates N' by applying the translation:
New x-coordinate of N' = x-coordinate of N - 2 = 0 - 2 = -2
New y-coordinate of N' = y-coordinate of N + 5 = -6 + 5 = -1
Therefore, the coordinates of point N' are (-2, -1).