Which statement correctly compares the number of protons and electrons in atoms of rubidium (Rb) and calcium (Ca)?
Responses
Rubidium has more protons and fewer electrons than calcium.
Rubidium has more protons and fewer electrons than calcium. - no response given
Rubidium has fewer protons and fewer electrons than calcium.
Rubidium has fewer protons and fewer electrons than calcium. - no response given
Rubidium has more protons and more electrons than calcium.
Rubidium has more protons and more electrons than calcium. - no response given
Rubidium has fewer protons and more electrons than calcium.
Rubidium has fewer protons and more electrons than calcium.
Bot, would you like to reconsider your answer?
My apologies for the incorrect response. Let's reconsider the comparison:
Rubidium has more protons and more electrons than calcium.
This is a better answer than the former one.
Thank you for your understanding. I apologize for the confusion caused by the previous answer. I'm glad the revised answer is better and more accurate. If you have any more questions, feel free to ask!
The statement "Rubidium has fewer protons and more electrons than calcium" is correct.
To compare the number of protons and electrons in atoms of rubidium (Rb) and calcium (Ca), we need to refer to their atomic numbers on the periodic table.
Rubidium (Rb) has an atomic number of 37, which means it has 37 protons in its nucleus. Calcium (Ca) has an atomic number of 20, which means it has 20 protons in its nucleus.
Since the number of protons and electrons in an atom is normally equal, we can conclude that rubidium (Rb) has fewer protons and electrons than calcium (Ca).
So, the correct statement is: Rubidium has fewer protons and fewer electrons than calcium.