Two of the dimensions of the triangle are 5 1/10 centimeters and 7 1/5 centimeters. The total distance the ant traveled is 20 centimeters. What is the length of the third side of the triangle?
i dont understand please explain in an easier way
To find the length of the third side of the triangle, we can subtract the sum of the two given side lengths from the total distance traveled by the ant.
The sum of the two given side lengths is (5 1/10) + (7 1/5) = (51/10) + (36/5) = (51/10) + (72/10) = (123/10) = 12 3/10 = (12 3/10)(10/10) = (123/10)(10/10) = 123/10.
The length of the third side of the triangle is 20 - (123/10) = (200/10) - (123/10) = (200 - 123)/10 = 77/10 = 7 7/10 centimeters.
Therefore, the length of the third side of the triangle is 7 7/10 centimeters.
explain in easier way please
Sure! To find the length of the third side of the triangle, we need to subtract the lengths of the other two sides from the total distance traveled by the ant.
The length of one side is 5 1/10 centimeters. This is the same as 5.1 centimeters.
The length of the other side is 7 1/5 centimeters. This is the same as 7.2 centimeters.
So, the sum of these two side lengths is 5.1 + 7.2 = 12.3 centimeters.
The total distance traveled by the ant is 20 centimeters.
To find the length of the third side, we subtract the sum of the other two side lengths from the total distance: 20 - 12.3 = 7.7 centimeters.
Therefore, the length of the third side of the triangle is 7.7 centimeters.
A third ant walks around the perimeter of another rectangular sheet of paper. The dimensions of this sheet of paper are given in decimal numbers expressed to the hundredth place, with the tenths and hundredths digits being non-zero. If the ant travels between 19 and 19 centimeters, what are the dimensions of the sheet of paper? Give one possibility.
Let's suppose the length of the rectangular sheet of paper is L centimeters and the width is W centimeters.
The perimeter of the rectangle is given by the formula: P = 2(L + W).
Given that the ant travels between 19 and 19 centimeters, we can set up the following inequality: 19 < 2(L + W) ≤ 19.
Simplifying the inequality, we get: 9.5 < L + W ≤ 9.5.
Now, let's look for possible values of L and W that satisfy the inequality.
One possibility could be L = 4.75 centimeters and W = 4.75 centimeters.
With these values, the perimeter of the rectangle is P = 2(4.75 + 4.75) = 19 centimeters. So the ant would travel a distance of exactly 19 centimeters.
Therefore, one possible dimension for the rectangular sheet of paper is L = 4.75 centimeters and W = 4.75 centimeters.
please explain in an easier way
Certainly! Let's imagine a rectangular sheet of paper. We know that the ant walks around the perimeter of this rectangular sheet, which means it walks along all four sides.
The length of the sheet is called L and the width is called W. The perimeter of a rectangle is simply the sum of all four sides.
We're told that the ant's total distance traveled is between 19 and 19 centimeters. That means the perimeter of the rectangle must be exactly 19 centimeters.
So, we want to find values for L and W that make the perimeter add up to 19.
One possibility is if both the length and width of the rectangle are equal to 4.75 centimeters. In that case, the length plus the width is 4.75 + 4.75 = 9.5 centimeters. And since the perimeter is the sum of both sides doubled, we have 2(9.5) = 19 centimeters. This satisfies the condition given.
Therefore, one possible dimension for the rectangular sheet of paper is a length of 4.75 centimeters and a width of 4.75 centimeters.
wrong it is between 18 and 19 centimeters
Apologies for the confusion. Let's redefine the problem:
We have a rectangular sheet of paper, and the length is denoted as L centimeters and the width as W centimeters.
The perimeter of the rectangle is given by the formula: P = 2(L + W).
We are told that the ant travels a distance between 18 and 19 centimeters.
To satisfy this condition, we need to find values for L and W that make 2(L + W) between 18 and 19.
One possibility is if L = 9 centimeters and W = 0.5 centimeters.
In this case, the perimeter will be P = 2(9 + 0.5) = 19 centimeters, which is within the given range.
Therefore, one possible dimension for the rectangular sheet of paper is a length of 9 centimeters and a width of 0.5 centimeters.