What is the least integer whose square root is an irrational number between 5 and 7?
25
13
6
26
The least integer whose square root is an irrational number between 5 and 7 is 26.
Calculating the square root of 26 results in a decimal approximation of approximately 5.099, which falls between 5 and 7.
To find the least integer whose square root is an irrational number between 5 and 7, we need to find the smallest perfect square between 5^2 and 7^2.
The smallest perfect square greater than 5^2 is 6^2, which equals 36.
The smallest perfect square less than 7^2 is 6^2 as well.
Therefore, the least integer whose square root is an irrational number between 5 and 7 is 6.