mol KHP = (0.7719g)(1 mol KHP/204.2g) = .0038mol
Where are the moles of NaOH?
I know that there are 0.02637 L of NaOH
and I know M = mol/l
I know there are 40g NaOH/mol NaOH
There is 1 mol of NaOH in the balanced equation
But I do not have grams of NaOH
If you know M = mol/L, doesn't it follow that mols = M x L? :-)
So mols NaOH = M(NaOH) x L(NaOH).
mols NaOH = mols KPH (from the titration)
L(NaOH) is given.
Solve for M(NaOH) which is what you want.
The whole concept of a titration is that you are adding moles of one reagent (from a buret, usually) to moles of another reagent (either in solid form or liquid form) and you have an indicator that tells you when to stop. [Technically, you are adding equivalents of one reagent to equivalents of another reagent]. But the NEW chemistry doesn't use equivalents. Pity.
To find the moles of NaOH, you need to know the mass of NaOH. However, in the information you provided, there is no given mass of NaOH. Without the mass of NaOH, you cannot directly calculate the moles of NaOH.
If you have additional information such as the concentration of NaOH or the volume of NaOH solution used, you can use the formula M = mol/L to calculate the moles of NaOH.
Here's how you can calculate the moles of NaOH if you have the concentration and volume:
1. Use the formula M = mol/L, where M is the concentration in mol/L and L is the volume in liters.
2. Rearrange the formula to solve for mol: mol = M * L.
3. Substitute the known values into the equation and calculate the moles of NaOH.
For example, if you have the concentration of NaOH as 0.5 mol/L and the volume of NaOH solution used as 0.02637 L, you can calculate the moles of NaOH as follows:
mol = (0.5 mol/L) * (0.02637 L)
mol = 0.013185 mol
Thus, the moles of NaOH in this example would be 0.013185 mol.