Shantel offers online tutorial services. She charges $25.00 an hour per student. Her budget tracker reflects a total of $3,200.00 monthly expenses. How many hours must Shantel work each month to earn a monthly profit of at least $600.00?
Let x be the number of hours Shantel must work each month.
Shantel's total monthly earning is 25x dollars.
Her expenses for the month are $3,200.00.
Her monthly profit is given by the equation 25x - 3200 = 600.
Adding 3200 to both sides of the equation, we get 25x = 3800.
Dividing both sides of the equation by 25, we get x = <<152=152>>152.
Therefore, Shantel must work at least 152 hours each month to earn a monthly profit of at least $600.00. Answer: \boxed{152}.
La’Shondra solves the inequality 6+3x≤24. She begins by subtracting 6 from both sides of the inequality and then divides both sides of the equivalent inequality by a number. What is the number?
La'Shondra subtracts 6 from both sides of the inequality: 6 + 3x - 6 ≤ 24 - 6
This simplifies to:
3x ≤ 18
To isolate x, La'Shondra needs to divide both sides of the inequality by 3:
3x/3 ≤ 18/3
x ≤ 6
Therefore, the number La'Shondra divides both sides of the equivalent inequality by is 3. Answer: \boxed{3}.
Solve the inequality Rx>10, where R is a number greater than 0.
To solve the inequality Rx > 10, we need to divide both sides of the inequality by R. However, we need to be careful because the value of R is greater than 0.
If R is positive, we can divide by R without changing the direction of the inequality:
(Rx)/R > 10/R
x > 10/R
Therefore, the solution to the inequality Rx > 10, where R is a number greater than 0, is x > 10/R.
Solve the inequality Ay+3<12, where A is a number greater than 0.
To solve the inequality Ay + 3 < 12, we need to isolate y.
First, subtract 3 from both sides of the inequality:
Ay + 3 - 3 < 12 - 3
Ay < 9
Next, to isolate y, we divide both sides of the inequality by A. Since A is a number greater than 0, we can divide without changing the direction of the inequality:
(Ay)/A < 9/A
y < 9/A
Therefore, the solution to the inequality Ay + 3 < 12, where A is a number greater than 0, is y < 9/A.
Jorelle is planning a 5-day vacation. The trip will cost him $1,300.00 for airfare, food, and itineraries. He plans to stay in a hotel room for $80.00 per night. He only has $950.00 in savings, but he earns $25.00 per hour from his online tutoring services. Create a linear inequality in one variable that would best translate the problem. Determine the minimum number of hours Jorelle must tutor so he can have enough money for the trip
Let x be the number of hours Jorelle must tutor.
Jorelle earns $25.00 per hour, so his total earnings from tutoring will be 25x dollars.
Jorelle's total expenses for the trip, including airfare, food, itineraries, and hotel, are $1,300.00 + ($80.00 per night x 5 nights) = $1,300.00 + $400.00 = $1,700.00.
Jorelle only has $950.00 in savings.
To determine the minimum number of hours Jorelle must tutor so he can have enough money for the trip, we need to set up an inequality.
His total earnings from tutoring (25x) must be greater than or equal to his total expenses for the trip ($1,700.00).
So, the linear inequality in one variable that would best translate the situation is:
25x ≥ 1700
Therefore, Jorelle must tutor for a minimum of 68 hours (25x = 1700, x = 68) in order to have enough money for the trip. Answer: \boxed{68}.
Jorelle is planning a 5-day vacation. The trip will cost him $1,300.00 for airfare, food, and itineraries. He plans to stay in a hotel room for $80.00 per night. He only has $950.00 in savings, but he earns $25.00 per hour from his online tutoring services. Create a linear inequality in one variable that would best translate the problem. Determine the minimum number of hours Jorelle must tutor so he can have enough money for the trip.(1 point)
Responses
950+25x≤1,300; at most 14 hours
950 plus 25 x less-than-or-equal-to 1,300 ; at most 14 hours
950+25x≥1,300; at least 14 hours
950 plus 25 x greater-than-or-equal-to 1,300 ; at least 14 hours
950+25x≤1,700; at most 30 hours
950 plus 25 x less-than-or-equal-to 1,700 ; at most 30 hours
950+25x≥1,700; at least 30 hours