y=x2+8x-6 what is the vertex
To find the vertex of the quadratic equation y = x^2 + 8x - 6, we can use the formula x = -b/2a.
In this equation, a = 1 (coefficient of x^2) and b = 8 (coefficient of x).
Plugging these values into the formula, we get:
x = -8/(2*1)
x = -8/2
x = -4
To find the value of y at x = -4, we substitute this value into the original equation:
y = (-4)^2 + 8(-4) - 6
y = 16 - 32 - 6
y = -22
Therefore, the vertex of the quadratic equation y = x^2 + 8x - 6 is (-4, -22).
To find the vertex of the quadratic equation y = x^2 + 8x - 6, we need to use a formula. The vertex of a quadratic equation in the form y = ax^2 + bx + c can be found using the formula x = -b / (2a).
In this equation, a = 1, b = 8, and c = -6.
Substituting these values into the formula, we have:
x = -(8) / (2 * 1)
x = -8 / 2
x = -4
Now, to find the y-coordinate of the vertex, we substitute this value of x into the original equation:
y = (-4)^2 + 8(-4) - 6
y = 16 - 32 - 6
y = -22
Therefore, the vertex of the quadratic equation y = x^2 + 8x - 6 is (-4, -22).