In inverting schmitt trigger circuit, the supply voltage is ± 12V. What is the maximum output voltage?
r1 = 10kΩ
r2 = 10lkΩ
To determine the maximum output voltage of an inverting Schmitt trigger circuit, we need to know the threshold voltages of the circuit.
The threshold voltage (Vt+) at which the output switches from low to high is calculated using the formula:
Vt+ = Vref * (1 + (R2/R1))
Similarly, the threshold voltage (Vt-) at which the output switches from high to low is calculated using the formula:
Vt- = Vref * (1 - (R2/R1))
Since the circuit is powered by ± 12V, the reference voltage (Vref) would typically be half the supply voltage, i.e., 6V in this case.
Therefore,
Vt+ = 6V * (1 + (10kΩ / 10kΩ))
Vt+ = 12V
Vt- = 6V * (1 - (10kΩ / 10kΩ))
Vt- = 0V
As the maximum output voltage (Vout) is equivalent to the supply voltage (+12V or -12V), the maximum output voltage in this inverting Schmitt trigger circuit would be ± 12V.
Question 35 options:
a) almost +10 V
b) + 5V
c) almost -10 V
d) - 5 V
In the given inverting Schmitt trigger circuit, the maximum output voltage will be equal to the supply voltage, which is ± 12V. Thus, the correct option is:
a) almost +10 V
To determine the maximum output voltage of an inverting Schmitt trigger circuit, you need to consider the threshold voltages and the voltage level of the supply.
The formula to calculate the output voltage is:
Vout = -(Vsaturation) * (R2 / (R1 + R2))
Where:
Vout is the output voltage
Vsaturation is the saturation voltage of the op-amp, which is usually close to the supply voltage
R1 is the resistance connected to the non-inverting input
R2 is the resistance connected to the output
In this case, the supply voltage is ±12V, so Vsaturation would be 12V.
Given:
R1 = 10kΩ
R2 = 10kΩ
Using the formula, we can calculate the maximum output voltage:
Vout = -(12V) * (10kΩ / (10kΩ + 10kΩ))
Simplifying the equation:
Vout = -(12V) * (10kΩ / 20kΩ)
Vout = -6V
Therefore, the maximum output voltage is -6V.