A student drops the same 10 kilogram ball from heights of one, two, and three meters. Which bar graph accurately shows the ball’s kinetic energy when dropped from each height?(1 point) Responses
Unfortunately, without any suggested bar graphs to choose from, I cannot accurately answer this question.
bruh
To answer this question, we need to understand the formula for kinetic energy which is given by the equation:
KE = 1/2 * m * v^2
where KE is the kinetic energy, m is the mass of the object (in this case, the 10 kilogram ball), and v is the velocity of the object.
Since the ball is dropped, it starts with an initial velocity of 0 and gains speed as it falls.
To calculate the velocity at each height, we can use the equation:
v = sqrt(2 * g * h)
where g is the acceleration due to gravity (approximately 9.8 m/s^2) and h is the height.
Using this information, we can determine the kinetic energy at each height and create the bar graph.
Let's calculate the kinetic energy at each height:
Height = 1 meter:
v = sqrt(2 * 9.8 * 1) = sqrt(19.6) ≈ 4.42 m/s
KE = 1/2 * 10 * (4.42)^2 ≈ 97.4 Joules
Height = 2 meters:
v = sqrt(2 * 9.8 * 2) = sqrt(39.2) ≈ 6.26 m/s
KE = 1/2 * 10 * (6.26)^2 ≈ 196.4 Joules
Height = 3 meters:
v = sqrt(2 * 9.8 * 3) = sqrt(58.8) ≈ 7.67 m/s
KE = 1/2 * 10 * (7.67)^2 ≈ 293.3 Joules
Now, let's draw the bar graph accurately representing the kinetic energy at each height:
Height (m) | Kinetic Energy (Joules)
----------------------------------
1 | 97.4
2 | 196.4
3 | 293.3
(Note: The scale of the bar height may vary depending on the range and intervals chosen.)
To determine the kinetic energy of the ball when dropped from different heights, we need to use the equation for kinetic energy:
Kinetic Energy (K.E.) = 0.5 * mass * velocity^2
Since the mass of the ball is 10 kilograms, we can see that the kinetic energy depends on the velocity squared. To calculate the velocity, we can use the equation for free fall:
velocity = √(2 * gravity * height)
Where gravity is approximately 9.8 m/s^2 (acceleration due to gravity) and height is the dropping height in meters.
Now, let's calculate the kinetic energy for each dropping height:
For a height of 1 meter:
velocity = √(2 * 9.8 * 1) ≈ 4.43 m/s
K.E. = 0.5 * 10 * (4.43)^2 ≈ 97.97 Joules
For a height of 2 meters:
velocity = √(2 * 9.8 * 2) ≈ 6.26 m/s
K.E. = 0.5 * 10 * (6.26)^2 ≈ 196.5 Joules
For a height of 3 meters:
velocity = √(2 * 9.8 * 3) ≈ 7.67 m/s
K.E. = 0.5 * 10 * (7.67)^2 ≈ 292.9 Joules
Now that we have calculated the kinetic energy values for each height, we can construct a bar graph. The x-axis should represent the different heights (1, 2, and 3 meters), and the y-axis should represent the kinetic energy values (97.97, 196.5, and 292.9 Joules). The bars on the graph should accurately represent these values.