Allen weighs 44 kg. Miller weighs half as much as Allen, and James weighs 3 kg more than Miller.
What is their weight all together?
Miller weighs half as much as Allen, so Miller weighs 44 kg / 2 = <<44/2=22>>22 kg.
James weighs 22 kg + 3 kg = <<22+3=25>>25 kg.
Therefore, their total weight is 44 kg + 22 kg + 25 kg = <<44+22+25=91>>91 kg. Answer: \boxed{91}.
Mary and Peter shared a cookie. Mary ate three tenths. Peter ate four tenths. How much is left?
Together, Mary and Peter ate 3/10 + 4/10 = 7/10 of the cookie.
There is 1 - 7/10 = 3/10 of the cookie left.
Therefore, there is 3/10 of the cookie left. Answer: \boxed{\frac{3}{10}}.
Which has a different answer?
7 + 2 - 4
2 + 7 - 4
7 - 4 + 2
4 + 7 - 2
The four expressions have different numbers, but they all evaluate to the same answer.
7 + 2 - 4 = 9
2 + 7 - 4 = 5
7 - 4 + 2 = 5
4 + 7 - 2 = 9
So, none of the expressions have a different answer.
so the awnser is?
a b c or d
The answer is either a) 9 or d) 9, depending on which expression you are referring to.
Which is NOT true?
11 = 11
11 = 18 - 7
11 + 5 = 15 + 11
11 + 3 = 6 + 8
The statement "11 + 3 = 6 + 8" is NOT true because it evaluates to 14 on the left side and 14 on the right side, not equal to each other.
To find the weight of Allen, Miller, and James together, we need to calculate their individual weights first and then add them up.
Given:
Allen weighs 44 kg.
Since Miller weighs half as much as Allen, we can find Miller's weight by dividing Allen's weight by 2:
Miller's weight = 44 kg / 2 = 22 kg.
James weighs 3 kg more than Miller, so we add 3 kg to Miller's weight to find James' weight:
James' weight = 22 kg + 3 kg = 25 kg.
Now that we have the weights of all three individuals, we can add them together to find their total weight:
Total weight = Allen's weight + Miller's weight + James' weight
Total weight = 44 kg + 22 kg + 25 kg
Calculating the sum:
Total weight = 91 kg.
Therefore, the total weight of Allen, Miller, and James combined is 91 kg.