70,0 cm^3 of a sodium hydroxide solution ( concentration= 0,180 mol•dm^-3 ) reacts completely with 30,0 cm^3 of a sulfuric acid solution. Write a balanced equation for the reaction.
The balanced equation for the reaction between sodium hydroxide (NaOH) and sulfuric acid (H2SO4) can be written as:
2 NaOH + H2SO4 -> Na2SO4 + 2 H2O
To determine the balanced equation for the reaction between sodium hydroxide (NaOH) and sulfuric acid (H2SO4), we need to identify the reactants and products involved.
The reactants are NaOH and H2SO4, and the products will be sodium sulfate (Na2SO4) and water (H2O).
The balanced equation for the reaction can be written as follows:
2NaOH + H2SO4 -> Na2SO4 + 2H2O
This equation indicates that 2 moles of NaOH react with 1 mole of H2SO4 to produce 1 mole of Na2SO4 and 2 moles of H2O.