1+7x+10x^2 solve
To solve the equation 1 + 7x + 10x^2, we can use the quadratic formula.
The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
Comparing the given equation to the standard quadratic form ax^2 + bx + c = 0, we have:
a = 10, b = 7, c = 1.
Plugging these values into the quadratic formula, we get:
x = (-7 ± √(7^2 - 4*10*1)) / (2*10)
Simplifying this expression further, we get:
x = (-7 ± √(49 - 40)) / 20
x = (-7 ± √9) / 20
x = (-7 ± 3) / 20
Solving for both values, we have:
x = (-7 + 3) / 20 = -4/20 = -1/5
x = (-7 - 3) / 20 = -10/20 = -1/2
So, the solutions to the equation 1 + 7x + 10x^2 = 0 are x = -1/5 and x = -1/2.
To solve the expression 1 + 7x + 10x^2, you can follow these steps:
Step 1: Rearrange the terms in descending order of the variable's exponent (x^2, x, constant term).
The expression becomes: 10x^2 + 7x + 1
Step 2: Factor out the common factors, if possible.
In this case, there are no common factors to factor out.
Step 3: Use the quadratic formula to find the roots of the quadratic equation.
The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / 2a
In the given expression, a = 10, b = 7, c = 1. Plugging these values into the quadratic formula:
x = (-7 ± √(7^2 - 4(10)(1))) / 2(10)
x = (-7 ± √(49 - 40)) / 20
x = (-7 ± √9) / 20
x = (-7 ± 3) / 20
So, the two solutions are:
x = (-7 + 3) / 20 = -4/20 = -1/5
x = (-7 - 3) / 20 = -10/20 = -1/2
Thus, the solutions to the quadratic equation 10x^2 + 7x + 1 are x = -1/5 and x = -1/2.