How many unpaired electrons are in Sm where z= 62 write the electrons configuration of +3 ion
In a neutral Sm atom (Z = 62), the electron configuration is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^6 5d^0 6p^0
To determine the number of unpaired electrons, we need to consider the last electron added, which is the 4f^6 electron. The 4f sublevel can hold a maximum of 14 electrons, so there are 8 electrons already paired up in the 4f orbital.
Thus, there are 6 unpaired electrons in a neutral Sm atom (Z = 62).
To write the electron configuration of the +3 ion, we remove 3 electrons from the neutral atom. Removing electrons from the outermost (highest energy) shell first, we will remove the 6s^2 electrons and one 4f^6 electron.
Therefore, the electron configuration of the Sm+3 ion is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 4f^5
The alloy SmCo5 forms a permanent magnet because both samarium and cobalt have unpaired electrons. a)How many unpaired electrons are in Sm where z= 62 b)write the electrons configuration of +3 ion
a) In a Sm atom (Z = 62), the electron configuration is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^6 5d^0 6p^0
To determine the number of unpaired electrons, we need to consider the last electron added, which is the 4f^6 electron. The 4f sublevel can hold a maximum of 14 electrons, so there are 8 electrons already paired up in the 4f orbital.
Thus, there are 6 unpaired electrons in a Sm atom (Z = 62).
b) To write the electron configuration of the +3 ion, we remove 3 electrons from the neutral atom. Removing electrons from the outermost (highest energy) shell first, we will remove the 6s^2 electrons and one 4f^6 electron.
Therefore, the electron configuration of the Sm+3 ion is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 4f^5
To determine the number of unpaired electrons in Sm (atomic number 62), we need to find its electron configuration.
The electron configuration of an atom can be determined by following the Aufbau principle, which states that electrons occupy the lowest energy levels first before filling higher levels. The electron configuration of Sm is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^6 5d^0
To determine the electron configuration of the +3 ion, we need to remove three electrons from the outermost shell (6s^2) first since the Sm ion has a +3 charge.
Therefore, the electron configuration of Sm+3 ion is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 4f^6 5d^0
Now, to determine the number of unpaired electrons in the Sm+3 ion, we need to look at the last partially filled subshell. In this case, it is the 4f subshell with 6 electrons.
Since the 4f subshell can hold a total of 14 electrons, and there are only 6 electrons in it, we can deduce that all 6 electrons are paired. Therefore, there are no unpaired electrons in the Sm+3 ion.