8x -3 y =-22
Y=10 + 4 x
To solve the system of equations, we can substitute the second equation into the first equation:
8x - 3(10 + 4x) = -22
Simplifying:
8x - 30 - 12x = -22
Combine like terms:
-4x - 30 = -22
Add 30 to both sides:
-4x = 8
Divide both sides by -4:
x = -2
Now substitute the value of x back into the second equation to find the value of y:
y = 10 + 4(-2)
y = 10 - 8
y = 2
Therefore, the solution to the system of equations is x = -2 and y = 2.
To solve the system of equations 8x - 3y = -22 and y = 10 + 4x, we can use substitution method.
Let's substitute the value of y from the second equation into the first equation:
8x - 3(10 + 4x) = -22
Now, simplify the equation:
8x - 30 - 12x = -22
Combine like terms:
-4x - 30 = -22
Now, isolate the variable x:
-4x = -22 + 30
-4x = 8
Divide both sides by -4 to solve for x:
x = 8 / -4
x = -2
Now that we have the value of x, substitute it back into the second equation to find the value of y:
y = 10 + 4(-2)
y = 10 - 8
y = 2
Therefore, the solution to the system of equations is x = -2 and y = 2.