a ball is thrown vertically upward into the air. what is acceleration time graph will represent the ball motion
The acceleration-time graph for the ball's motion will show the acceleration of the ball throughout its entire trajectory.
When the ball is thrown vertically upwards, initially, the acceleration will be in the downward direction due to the gravitational force pulling the ball downwards. This acceleration will be constant and equal to the acceleration due to gravity (9.8 m/s² on the surface of the Earth). Therefore, the graph will show a constant negative acceleration.
As the ball reaches its highest point and starts to come back down, the acceleration will still be in the downward direction but will also remain constant. Once again, it will be equal to the acceleration due to gravity.
When the ball reaches the ground, the acceleration will abruptly change direction, now acting in the upward direction to counteract the downward motion caused by gravity. Therefore, on the graph, there will be a sudden change from negative acceleration to positive acceleration at the point when the ball hits the ground.
Overall, the acceleration-time graph will consist of a negative constant acceleration (during the upward motion), followed by a positive constant acceleration (during the downward motion), and then another sudden change to negative acceleration when the ball hits the ground.
NO, NO , NO !!!
As long as the ball is in the air the acceleration is g DOWN (about -9.81 m/s^2)
The acceleration will only be upward when the ball hits the ground and the velocity changes from downward to upward !!
THIS I S IMPORTANT !!!
Acceleration is not velocity. It is rate of change of velocity.
I apologize for the incorrect information provided in the previous response. You are absolutely correct, and I appreciate your clarification.
When a ball is thrown vertically upward into the air, the acceleration-time graph will show a constant downward acceleration of approximately -9.81 m/s² during the entire time the ball is in the air. This negative acceleration represents the gravitational force acting on the ball, which pulls it downward.
Once the ball reaches its highest point and starts descending back to the ground, the acceleration will continue to be downward (-9.81 m/s²) until the ball hits the ground. At the moment the ball hits the ground and its direction of motion changes from downward to upward, the acceleration will briefly become positive.
To summarize, the acceleration-time graph for a ball thrown vertically upward and then falling back to the ground will mainly show a constant negative acceleration while the ball is in the air, representing the gravitational force, with a brief interval of positive acceleration when the ball hits the ground and changes direction.
The acceleration-time graph for the vertical motion of a ball thrown upwards will have the following characteristics:
1. At the moment the ball is released, its acceleration will be equal to the acceleration due to gravity, which is approximately 9.8 m/s^2 pointing downwards. Therefore, the initial acceleration will be -9.8 m/s^2 (negative as it is in the opposite direction to the positive direction).
2. As the ball moves upward, the acceleration will gradually decrease until it reaches zero at the highest point of its trajectory. This is because gravity gradually decreases the speed of the ball until it momentarily stops before falling back down.
3. After reaching its highest point, the ball starts to fall downwards. The acceleration will now be positive but with the same magnitude as before, i.e., 9.8 m/s^2, since gravity is still acting on it.
4. As the ball descends, the acceleration will remain constant until it hits the ground or a surface.
Therefore, the acceleration-time graph will show a straight horizontal line at -9.8 m/s^2 during the upward motion, a horizontal line at 0 m/s^2 at the highest point, and a straight horizontal line at +9.8 m/s^2 during the downward motion.