A bag contains three green Christmas ornaments and four gold ornaments. If you randomly pick a single ornament from the bag, what is the probability that it will be green?
There are a total of 3 + 4 = <<3+4=7>>7 ornaments in the bag.
The probability of picking a green ornament is 3/7. Answer: \boxed{\dfrac{3}{7}}.
To find the probability of picking a green ornament, we need to determine the total number of possible outcomes and the number of favorable outcomes.
Total number of ornaments = number of green ornaments + number of gold ornaments = 3 + 4 = 7
Number of favorable outcomes (green ornaments) = 3
Therefore, the probability of picking a green ornament is given by:
Probability = Number of favorable outcomes / Total number of possible outcomes
= 3 / 7
= 3/7
So, the probability of picking a green ornament is 3/7.