Expand(3x-4)(x+2)-(x-2)
To expand the expression (3x-4)(x+2)-(x-2), we can use the distributive property to multiply each term in the first parentheses by each term in the second parentheses, and then subtract the result of (x-2).
First, let's multiply each term:
(3x-4)(x+2) = 3x*x + 3x*2 - 4*x - 4*2
= 3x^2 + 6x - 4x - 8
= 3x^2 + (6x - 4x) - 8
= 3x^2 + 2x - 8
Now, let's subtract (x-2) from the previous result:
(3x^2 + 2x - 8) - (x - 2) = 3x^2 + 2x - 8 - x + 2
= 3x^2 + (2x - x) - (8 - 2)
= 3x^2 + x - 6
Therefore, the expansion of (3x-4)(x+2)-(x-2) is 3x^2 + x - 6.
To expand the expression (3x-4)(x+2)-(x-2), we can use the distributive property.
Step 1: Distribute the terms from the first set of parentheses to the terms inside the second set of parentheses:
(3x-4)(x+2) = 3x(x+2) - 4(x+2)
Step 2: Multiply the terms inside the parentheses:
= 3x^2 + 6x - 4x - 8
Step 3: Combine like terms:
= 3x^2 + 2x - 8
Now let's subtract (x-2) from this result:
(3x^2 + 2x - 8) - (x-2)
Step 4: Distribute the negative sign to the terms inside the second set of parentheses:
= 3x^2 + 2x - 8 - x + 2
Step 5: Combine like terms:
= 3x^2 + x - 6
So the expanded form of (3x-4)(x+2)-(x-2) is 3x^2 + x - 6.