a 100 kg mass dropped from a height of 3.0 m. the kinetic energy before striking the ground is
To find the kinetic energy before the mass strikes the ground, we can use the formula for kinetic energy:
Kinetic Energy = (1/2) * mass * velocity^2
Given:
Mass (m) = 100 kg
Height (h) = 3.0 m
Acceleration due to gravity (g) = 9.8 m/s^2 (assuming no air resistance)
First, we need to find the velocity of the mass just before it hits the ground using the equation for potential energy:
Potential Energy = mass * gravity * height
Potential Energy = 100 kg * 9.8 m/s^2 * 3.0 m
= 2940 J
Since the potential energy is converted into kinetic energy as the mass falls, the kinetic energy just before striking the ground is equal to the potential energy.
Therefore, the kinetic energy before striking the ground is 2940 Joules.
To determine the kinetic energy of the 100 kg mass before it strikes the ground, we can use the formula for kinetic energy:
Kinetic Energy = (1/2) * mass * velocity^2
First, let's calculate the velocity of the falling mass using the principle of conservation of energy. The potential energy of the mass at a height of 3.0 m can be converted into kinetic energy:
Potential Energy = Mass * Gravity * Height
where:
Mass = 100 kg (mass of the object)
Gravity = 9.8 m/s^2 (acceleration due to gravity)
Height = 3.0 m (height from which the mass is dropped)
Potential Energy = 100 kg * 9.8 m/s^2 * 3.0 m
Now, let's convert the potential energy into kinetic energy:
Kinetic Energy = Potential Energy
Substituting the value of potential energy calculated:
Kinetic Energy = 100 kg * 9.8 m/s^2 * 3.0 m
Now, we can solve for kinetic energy:
Kinetic Energy = 100 kg * 9.8 m/s^2 * 3.0 m
Kinetic Energy ≈ 2940 J
Therefore, the kinetic energy of the 100 kg mass before striking the ground is approximately 2940 Joules.