M is inversely proportional to square of 1. If M=9 when 1=2 find M when 1=10 and 1 when M=1
To solve this problem, we can set up a proportion using the inverse proportionality:
M = k/1^2
where k is the constant of proportionality. We can solve for k by substituting the values of M and 1 given:
9 = k/2^2
9 = k/4
k = 4 * 9 = 36
Now we can use k to find M when 1 = 10:
M = 36/10^2
M = 36/100
M = 0.36
And to find 1 when M = 1:
1 = 36/M^2
1 = 36/1^2
1 = 36/36
1 = 1
So, when 1 = 10, M = 0.36 and when M = 1, 1 = 1.
To find the value of M when 1 = 10, we can use the inverse proportionality relationship.
Given that M is inversely proportional to the square of 1, we can write the equation as:
M = k / (1^2)
where k is the constant of proportionality.
To find the value of k, we can use the given information that M = 9 when 1 = 2:
9 = k / (2^2)
9 = k / 4
k = 36
Now we can substitute the value of k into the equation and solve for M when 1 = 10:
M = 36 / (10^2)
M = 36 / 100
M = 0.36
Therefore, when 1 = 10, M is equal to 0.36.
To find the value of 1 when M = 1, we can use the same equation:
M = k / (1^2)
Now, substitute M = 1 and solve for 1:
1 = k / (1^2)
1 = k / 1
k = 1
Therefore, when M = 1, 1 is equal to 1.