The result from the solving of this inequality 3(x-6)<(x-1) is
2+2
2 + 2 = 4
3(x-6)<(x-1)
3x - 18 < x - 1 (distribute the 3)
3x - x < 18 - 1 (move x to the left and 1 to the right)
2x < 17
x < 17/2
The result of the inequality is x is less than 17/2.
A ship sails from p to Q on a bearing of 60°,and then from Q to R on a bearing of 300°. PQ=8km and QR =5km.find
a: How far is the ship now from its starting point?
b:The appropriate bearing of R from 1 is
The mean of a set of number is 68,65, x, 69, 77,48,64 and 67. find x
To find the value of x, we need to calculate the mean of the given set of numbers and set it equal to 68.
Mean = (sum of all numbers) / (number of numbers)
Therefore, we can set up the equation:
(68 + 65 + x + 69 + 77 + 48 + 64 + 67) / 8 = 68
Now, let's solve for x:
(351 + x) / 8 = 68
Multiply both sides by 8:
351 + x = 544
Subtract 351 from both sides:
x = 544 - 351
x = 193
Therefore, the value of x is 193.
The average of 10 boys was 12 years.A boy of 15 years was replaced with that of 5 years.Find the new average age of the boys
The total age of the 10 boys before the replacement is 10 * 12 = 120 years.
To find the new average age, we need to consider the sum of their ages after the replacement.
Since a boy of 15 years was replaced with a boy of 5 years, the total age difference is 15 - 5 = 10 years.
The new total age of the boys is 120 - 10 = 110 years.
To find the new average age, we divide the new total age by the number of boys (which is still 10):
New average age = 110 / 10 = 11 years.
Therefore, the new average age of the boys is 11 years after the replacement.
Twenty girls and boys sat for an examination.The mean marks obtained by the girls and boys were 62 and 57 respectively.if the total scores for both girls and boys were 2950, find Y
Let y represent the number of boys in the group.
Since there are 20 students total, the number of girls would be 20 - y.
The total marks obtained by the girls would be the mean marks (62) multiplied by the number of girls.
Similarly, the total marks obtained by the boys would be the mean marks (57) multiplied by the number of boys.
So, we can form the following equations:
62(20 - y) + 57y = 2950
Expanding the equation:
1240 - 62y + 57y = 2950
Combining like terms:
-5y = 170
Dividing both sides by -5:
y = -34
Since we cannot have a negative number of boys, this solution does not make sense in the context of the problem.
Therefore, there may have been an error in the given information or calculations. Please double-check and provide the correct information for further assistance.