If the smallest angle in an isosceles triangle is 36°, what is the size of each of the other two larger angles?
In an isosceles triangle, two angles are equal in size. Let's call the size of these two angles x.
We know that the smallest angle is 36°, so one of the equal angles is 36°.
Therefore, we have:
x + x + 36° = 180° (the sum of the angles in a triangle)
2x + 36° = 180°
2x = 144°
x = 144°/2
x = 72°
So, each of the other two larger angles is 72°.
In an isosceles triangle, the two larger angles are equal in size. Let's denote the size of each of the two larger angles as x. Since the smallest angle is 36°, we can set up an equation:
36° + x + x = 180°
Combining like terms, we have:
36° + 2x = 180°
Subtracting 36° from both sides, we get:
2x = 144°
Dividing both sides by 2, we find:
x = 72°
Therefore, each of the other two larger angles in the isosceles triangle is 72°.