3. P =
(2𝑥𝑦)
3𝑐−5𝑦
, make y the subject of the
formula.
A. y = 2x2 — 5p
B. y =
(2𝑝+5𝑐)
𝑝
C. y =
3𝑝𝑥
(2𝑥+5𝑐)
D. y =
3𝑐𝑝
(2𝑥+5𝑝)
To make y the subject of the formula, we need to isolate y on one side of the equation.
Starting with the given formula:
P =
(2𝑥𝑦)
3𝑐−5𝑦
First, we need to get rid of the denominator in the equation. We can do this by multiplying both sides of the equation by the denominator:
P(3c - 5y) = 2xy
Expanding the left side of the equation:
3cP - 5Py = 2xy
Now, let's isolate y by moving all the terms containing y to one side of the equation:
-5Py = 2xy - 3cP
Divide both sides of the equation by -5P:
y = (2xy - 3cP) / (-5P)
Simplifying the expression:
y = -2xy/5P + 3cP/5P
Finally, we can simplify further by dividing both terms by their common factors:
y = -2x/5 + 3c/5
Therefore, the answer is D. y = -2x/5 + 3c/5.
To make y the subject of the formula P = (2xy)/(3c-5y), we need to isolate y on one side of the equation.
Step 1: Multiply both sides of the equation by (3c-5y) to eliminate the denominator.
(3c-5y) * P = (3c-5y) * (2xy)/(3c-5y)
Simplifying, we get:
P * (3c-5y) = 2xy
Step 2: Distribute P to both terms on the right side of the equation.
3cP - 5yP = 2xy
Step 3: Move the term with y to the left side of the equation.
-5yP = 2xy - 3cP
Step 4: Divide both sides of the equation by -5P to isolate y.
y = (2xy - 3cP)/(-5P)
Simplifying further, we get:
y = (2x - 3cP/5P)
The correct answer is option B: y = (2p+5c)/(p)