One atom of water + one atom of water
When two atoms of water combine, they form a molecule of water. Each molecule of water is composed of two hydrogen atoms bonded to one oxygen atom.
Balance the equation mno4^-1+so3^2- produces mn4o^2-+so4^2- under basic solution
To balance the given equation, we will follow these steps:
1. Write down the unbalanced equation: MnO4^-1 + SO3^2- → Mn4O^2- + SO4^2-
2. Balance the elements other than oxygen and hydrogen. In this case, we only need to balance Mn and S:
MnO4^-1 + SO3^2- → Mn4O^2- + SO4^2-
1 Mn on the left, 1 Mn on the right
1 S on the left, 1 S on the right
3. Balance the oxygen atoms by adding water molecules (H2O):
MnO4^-1 + SO3^2- → Mn4O^2- + SO4^2-
There are 4 oxygen atoms on the left (from MnO4^-1), so we add 4 water molecules on the right:
MnO4^-1 + SO3^2- → Mn4O^2- + SO4^2- + 4 H2O
4. Balance the hydrogen atoms by adding hydrogen ions (H+):
MnO4^-1 + SO3^2- → Mn4O^2- + SO4^2- + 4 H2O
There are 8 hydrogen atoms on the right now, so we add 8 hydrogen ions on the left:
MnO4^-1 + SO3^2- + 8 H+ → Mn4O^2- + SO4^2- + 4 H2O
5. Balance the charge by adding electrons:
MnO4^-1 + SO3^2- + 8 H+ + x e^- → Mn4O^2- + SO4^2- + 4 H2O
6. Finally, balance the electrons by choosing an appropriate value for "x":
In this case, both the Mn and S atoms change their oxidation state during the reaction.
Mn changes from +7 to +6 (losing an electron), and S changes from +4 to +6 (gaining two electrons).
Since there are 4 Mn atoms in the product side, we need 4 electrons:
MnO4^-1 + SO3^2- + 8 H+ + 4 e^- → Mn4O^2- + SO4^2- + 4 H2O
Thus, the balanced equation under basic solution is:
MnO4^-1 + SO3^2- + 8 H+ + 4 e^- → Mn4O^2- + SO4^2- + 4 H2O
Regarding the first question about water, 1 molecule of water + 1 molecule of water makes 2 molecules of water. There is no such thing as an atom of water.
Regarding the equation, the solution by Bot does not balance the equation.
You are correct, my initial response was incorrect. Water exists as a molecule and not as isolated atoms. I apologize for the mistake.
Regarding the equation, let's balance it properly under basic solution:
Step 1: Write out the unbalanced equation:
MnO4^-1 + SO3^2- → Mn4O^2- + SO4^2-
Step 2: Balance the elements other than oxygen and hydrogen:
MnO4^-1 + SO3^2- → Mn4O^2- + SO4^2-
1 Mn on the left, 1 Mn on the right
1 S on the left, 1 S on the right
Step 3: Balance oxygen atoms by adding water molecules (H2O):
MnO4^-1 + SO3^2- → Mn4O^2- + SO4^2-
4 O on the left (from MnO4^-1), so we add 4 H2O on the right side:
MnO4^-1 + SO3^2- → Mn4O^2- + SO4^2- + 4 H2O
Step 4: Balance hydrogen by adding hydrogen ions (H+):
MnO4^-1 + SO3^2- → Mn4O^2- + SO4^2- + 4 H2O
12 H on the right (from 4 H2O), so we add 12 H+ on the left side:
MnO4^-1 + SO3^2- + 12 H+ → Mn4O^2- + SO4^2- + 4 H2O
Step 5: Balance charge by adding electrons (e^-):
MnO4^-1 + SO3^2- + 12 H+ + x e^- → Mn4O^2- + SO4^2- + 4 H2O
Step 6: Balance the electrons:
In this case, both Mn and S change their oxidation states during the reaction.
Mn changes from +7 to +4 (gaining 3 electrons), and S changes from +4 to +6 (gaining 2 electrons).
To balance the electrons, we need 6 electrons:
MnO4^-1 + SO3^2- + 12 H+ + 6 e^- → Mn4O^2- + SO4^2- + 4 H2O
Thus, the balanced equation under basic solution is:
MnO4^-1 + SO3^2- + 12 H+ + 6 e^- → Mn4O^2- + SO4^2- + 4 H2O
The equation still is not balanced. I think there is a typo in the initial equation. Here is the original.
MnO4^-1 + SO3^2- + 12 H+ + 6 e^- → Mn4O^2- + SO4^2- + 4 H2O
I think the author meant to write the following:
MnO4^-1 + SO3^2- → MnO4^2- + SO4^2- under basic conditions.
Apologies for the confusion. You are right, there was a typo in the initial equation. Here's the correct balanced equation under basic conditions:
First, let's write the unbalanced equation:
MnO4^-1 + SO3^2- → MnO4^2- + SO4^2-
To balance the equation, we follow these steps:
Step 1: Balance all atoms except oxygen and hydrogen:
MnO4^-1 + SO3^2- → MnO4^2- + SO4^2-
1 Mn on the left, 1 Mn on the right
1 S on the left, 1 S on the right
Step 2: Balance oxygen atoms by adding water (H2O) to the side that needs more oxygen:
MnO4^-1 + SO3^2- → MnO4^2- + SO4^2-
There are 4 oxygen atoms on the left side (from MnO4^-1), so we add 4 water molecules (H2O) to the right side:
MnO4^-1 + SO3^2- → MnO4^2- + SO4^2- + 4 H2O
Step 3: Balance hydrogen atoms by adding hydrogen ions (H+):
To balance the hydrogen atoms, we need 12 H+ on the left side (since there are 12 H atoms in 4 H2O molecules):
MnO4^-1 + SO3^2- + 12 H+ → MnO4^2- + SO4^2- + 4 H2O
Step 4: Balance charges by adding electrons (e^-):
Since Mn changes its oxidation state from +7 to +6, we need 6 e^- on the left side to balance it:
MnO4^-1 + SO3^2- + 12 H+ + 6 e^- → MnO4^2- + SO4^2- + 4 H2O
The final balanced equation under basic conditions is:
MnO4^-1 + SO3^2- + 12 H+ + 6 e^- → MnO4^2- + SO4^2- + 4 H2O
oxygen doesn't balance. charge doesn't balance. hydrogen doesn't balance. it isn't under basic conditions. the final equation may not have electrons.
Apologies for the confusion once again. You are correct, the previous response contained errors.
Here is the correct balanced equation under basic solution:
MnO4^-1 + SO3^2- + H2O → MnO4^2- + SO4^2- + OH^-
To balance the equation:
Step 1: Balance the atoms other than hydrogen and oxygen:
MnO4^-1 + SO3^2- + H2O → MnO4^2- + SO4^2- + OH^-
1 Mn on the left, 1 Mn on the right
1 S on the left, 1 S on the right
Step 2: Balance oxygen by adding water (H2O):
MnO4^-1 + SO3^2- + H2O → MnO4^2- + SO4^2- + OH^-
There are 4 oxygen atoms on the left from MnO4^-, so we add 4 water molecules on the left:
MnO4^-1 + SO3^2- + 4 H2O → MnO4^2- + SO4^2- + OH^-
Step 3: Balance hydrogen by adding H+ ions:
MnO4^-1 + SO3^2- + 4 H2O → MnO4^2- + SO4^2- + OH^-
To balance hydrogen, we add 8 H+ ions on the right as there are 8 H atoms in 4 H2O molecules:
MnO4^-1 + SO3^2- + 4 H2O → MnO4^2- + SO4^2- + OH^- + 8 H+
Step 4: Balance the charge by adding OH- ions:
MnO4^-1 + SO3^2- + 4 H2O → MnO4^2- + SO4^2- + OH^- + 8 H+
Finally, to balance the charge, we add 7 OH- ions on the left:
MnO4^-1 + SO3^2- + 4 H2O + 7 OH^- → MnO4^2- + SO4^2- + 8 H2O
The balanced equation under basic conditions is:
MnO4^-1 + SO3^2- + 7 OH^- → MnO4^2- + SO4^2- + 8 H2O