3113four+2323four leaving your answer in base 10
To convert the given numbers 3113four and 2323four to base 10, we need to determine the value of each digit in the given base.
Let's assume that "four" represents the digit 4 in base 10.
For 3113four:
The rightmost digit is 4, which represents 4 in base 10.
The next digit is 1, which represents 1 in base 10.
The third digit is 1, which represents 1 in base 10.
The leftmost digit is 3, which represents 3 in base 10.
Therefore, 3113four in base 10 is equal to 3 * 4^3 + 1 * 4^2 + 1 * 4^1 + 3 * 4^0
= 3 * 64 + 1 * 16 + 1 * 4 + 3 * 1
= 192 + 16 + 4 + 3
= 215 in base 10.
Similarly, for 2323four:
The rightmost digit is 4, which represents 4 in base 10.
The next digit is 3, which represents 3 in base 10.
The third digit is 2, which represents 2 in base 10.
The leftmost digit is 2, which represents 2 in base 10.
Therefore, 2323four in base 10 is equal to 2 * 4^3 + 3 * 4^2 + 2 * 4^1 + 3 * 4^0
= 2 * 64 + 3 * 16 + 2 * 4 + 3 * 1
= 128 + 48 + 8 + 3
= 187 in base 10.
Therefore, when adding 3113four and 2323four and converting the result to base 10, we have:
215 + 187 = 402 in base 10.
in base 4,
3113+2323 = 12102 which is 402 in base 10
Apologies for the mistake in the previous response. You are correct.
In base 4, the addition of 3113four and 2323four is equal to 12102.
Converting 12102 from base 4 to base 10:
1 * 4^4 + 2 * 4^3 + 1 * 4^2 + 0 * 4^1 + 2 * 4^0
= 1 * 256 + 2 * 64 + 1 * 16 + 0 * 4 + 2 * 1
= 256 + 128 + 16 + 0 + 2
= 402 in base 10.
So, 12102 in base 4 is equal to 402 in base 10.
To subtract numbers in different bases, we need to convert them to the same base. In this case, since we have "four" as the base, we convert the numbers to base 10.
To do the conversion, we need to understand the value of "four" in base 10. Assuming "four" represents the digit 4, we can convert the given numbers as follows:
3113four = 3*(four^3) + 1*(four^2) + 1*(four^1) + 3*(four^0)
= 3*(4^3) + 1*(4^2) + 1*(4^1) + 3*(4^0)
= 3*(64) + 1*(16) + 1*(4) + 3*(1)
= 192 + 16 + 4 + 3
= 215
2323four = 2*(four^3) + 3*(four^2) + 2*(four^1) + 3*(four^0)
= 2*(4^3) + 3*(4^2) + 2*(4^1) + 3*(4^0)
= 2*(64) + 3*(16) + 2*(4) + 3*(1)
= 128 + 48 + 8 + 3
= 187
Now we can subtract them in base 10:
215 - 187 = 28
Therefore, the answer to 3113four - 2323four in base 10 is 28.