Herky was given the following system of equations to solve.
3 x minus 2 y = 17. x minus 3 y = 1.
What is the solution to the system?
(2, 7)
(StartFraction 20 Over 7 EndFraction, StartFraction 67 over 7 EndFraction)
(7, 2)
(StartFraction 67 Over 7 EndFraction, StartFraction 20 Over 7 EndFraction)
The solution to the system is (7, 2).
Which is true regarding the system of equations?
x minus 4 y = 1. 5 x minus 20 y = 4.
The system results in a false statement.
The system results in an intersection at one point.
The system results in many solutions because they are the same line.
The system results in a true state
The system results in a false statement.
In the system of equations, which variable would it be easiest to solve for?
2 x + 4 y = 26. 3 x + y = 9.
The easiest to solve for is x in the first equation.
The easiest to solve for is y in the first equation.
The easiest to solve for is x in the second equation.
The easiest to solve for is y in the second equation.
The easiest to solve for is y in the second equation.
What is the first step in solving the following system of equations?
3 x + y = 23. 8 x + 2 y = 23.
Substitute the value of y from one equation into the other equation.
Solve the first equation for y.
Subtract the second equation from the first equation.
Substitute the value of x from one equation into the other equation.
Solve the first equation for y.
Thomas was selling tickets to his school play. The tickets cost $5.00 for adults and $2.00 for children. He sold 200 tickets and collected $610. Which system represents the number of adult and child tickets that Thomas sold?
x + y = 200. 5 x + 2 y = 610.
x + y = 610. 5 x + 2 y = 200.
x + y = 200. x + 2 y = 610.
x + y = 200. 5 x + y = 610.
x + y = 200.
5 x + 2 y = 610.
In the system of equations below, which variable would it be easiest to solve for?
x + 4 y = 14. 3 x + 2 y = 12
The easiest to solve for is x in the first equation.
The easiest to solve for is y in the first equation.
The easiest to solve for is x in the second equation.
The easiest to solve for is y in the second equation.