Find the excess-3 code of the given binary number
1010, 0100, 0001
To find the excess-3 code, we need to add the binary number 0011 (which is 3 in binary) to each digit of the given binary number.
For 1010:
1 + 0011 = 0100
0 + 0011 = 0011
1 + 0011 = 0100
0 + 0011 = 0011
So the excess-3 code for 1010 is 0100 0011 0100 0011.
For 0100:
0 + 0011 = 0011
1 + 0011 = 0100
0 + 0011 = 0011
0 + 0011 = 0011
So the excess-3 code for 0100 is 0011 0100 0011 0011.
For 0001:
0 + 0011 = 0011
0 + 0011 = 0011
0 + 0011 = 0011
1 + 0011 = 0100
So the excess-3 code for 0001 is 0011 0011 0011 0100.
To find the excess-3 code of a binary number, you need to add 3 to each digit of the binary number. Here are the steps to find the excess-3 code for each given binary number:
1. For the binary number 1010:
- Add 3 to the first digit: 1 + 3 = 4
- Add 3 to the second digit: 0 + 3 = 3
- Add 3 to the third digit: 1 + 3 = 4
- Add 3 to the fourth digit: 0 + 3 = 3
Therefore, the excess-3 code for the binary number 1010 is 4334.
2. For the binary number 0100:
- Add 3 to the first digit: 0 + 3 = 3
- Add 3 to the second digit: 1 + 3 = 4
- Add 3 to the third digit: 0 + 3 = 3
- Add 3 to the fourth digit: 0 + 3 = 3
Therefore, the excess-3 code for the binary number 0100 is 3343.
3. For the binary number 0001:
- Add 3 to the first digit: 0 + 3 = 3
- Add 3 to the second digit: 0 + 3 = 3
- Add 3 to the third digit: 0 + 3 = 3
- Add 3 to the fourth digit: 1 + 3 = 4
Therefore, the excess-3 code for the binary number 0001 is 3334.
Note: The excess-3 code uses 4 digits, so if the binary number is shorter than 4 digits, you need to add leading zeros.