Translate triangle ABC 2 units left and 3 units up
Triangle ABC would be translated to triangle A'B'C' as follows:
A' = A (-2, 3)
B' = B (-2, 3)
C' = C (-2, 3)
So, the new coordinates of the vertices would be:
A' (-2 + x, 3 + y)
B' (-2 + x, 3 + y)
C' (-2 + x, 3 + y)
where x is the original x-coordinate and y is the original y-coordinate.
To translate a triangle, we need to move each of its vertices the same distance and in the same direction. In this case, we will move triangle ABC 2 units to the left and 3 units up.
To translate point A, we will subtract 2 from its x-coordinate and add 3 to its y-coordinate.
New coordinates of point A: (A_x - 2, A_y + 3)
To translate point B, we will subtract 2 from its x-coordinate and add 3 to its y-coordinate.
New coordinates of point B: (B_x - 2, B_y + 3)
To translate point C, we will subtract 2 from its x-coordinate and add 3 to its y-coordinate.
New coordinates of point C: (C_x - 2, C_y + 3)
Therefore, the translated triangle ABC will have the new coordinates:
A' = (A_x - 2, A_y + 3)
B' = (B_x - 2, B_y + 3)
C' = (C_x - 2, C_y + 3)