An extension on a spring when 5g was hung was 0.56cm.If Hooke's law is obeyed, what is the extension cost by a load of 20g(live answer in cm
Assuming that the spring follows Hooke's law, we can use the formula:
F = kx
where F is the force applied, x is the extension, and k is the spring constant. We can rearrange this equation to solve for k:
k = F/x
where F = 5g and x = 0.56cm:
k = (5g)/(0.56cm) = 8.93 g/cm
Now we can use this value of k to find the extension caused by a load of 20g:
F = 20g
x = F/k = (20g)/(8.93 g/cm) = 2.24 cm
Therefore, the extension caused by a load of 20g is 2.24 cm.
To find the extension caused by a load of 20g, we can use Hooke's Law, which states that the extension of a spring is directly proportional to the load applied.
Given:
Load 1 = 5g
Extension 1 = 0.56cm
We can set up a proportion using the given information:
Load 1 / Extension 1 = Load 2 / Extension 2
Since the units of load and extension are the same, we can use the proportion as:
5g / 0.56cm = 20g / x
Simplifying this proportion, we get:
5 / 0.56 = 20 / x
Cross-multiplying, we find:
5x = (0.56) * 20
Now, simplify further:
5x = 11.2
Divide both sides by 5 to solve for x:
x = 11.2 / 5
x ≈ 2.24
Therefore, the extension caused by a load of 20g is approximately 2.24 cm.