What is the volume of a 0.1 M HCL solution containing one 1.46GM of HCL?
To find the volume of a 0.1 M HCl solution containing 1.46 grams of HCl, we can use the formula:
moles = mass / molar mass
First, we need to calculate the number of moles of HCl:
moles = 1.46 g / 36.46 g/mol = 0.04 moles
Now, we can calculate the volume of the solution using the formula:
Molarity = moles / volume (in liters)
0.1 M = 0.04 moles / volume
Volume = 0.04 moles / 0.1 M = 0.4 liters or 400 milliliters
Therefore, the volume of the 0.1 M HCl solution containing 1.46 grams of HCl is 400 milliliters.
What is the volume of a 0.2 M AgNO3 solution containing 8.5 grams of AgNO3
To find the volume of a 0.2 M AgNO3 solution containing 8.5 grams of AgNO3, we can use the formula:
moles = mass / molar mass
First, we need to calculate the number of moles of AgNO3:
molar mass of AgNO3 = 107.87 + 14.01 + 3(16.00) = 169.87 g/mol
moles = 8.5 g / 169.87 g/mol = 0.05 moles
Now, we can calculate the volume of the solution using the formula:
Molarity = moles / volume (in liters)
0.2 M = 0.05 moles / volume
Volume = 0.05 moles / 0.2 M = 0.25 liters or 250 milliliters
Therefore, the volume of the 0.2 M AgNO3 solution containing 8.5 grams of AgNO3 is 250 milliliters.
To find the volume of the 0.1 M HCl solution, we need to use the equation for molarity:
Molarity (M) = Number of moles (n) / Volume in liters (V)
First, let's calculate the number of moles of HCl using the given mass:
Mass (m) = 1.46 g
Molar mass (Mm) = 36.46 g/mol (mass of HCl)
Number of moles (n) = Mass (m) / Molar mass (Mm)
n = 1.46 g / 36.46 g/mol
Now, let's calculate the volume of the 0.1 M HCl solution using the molarity formula:
Molarity (M) = 0.1 M
Number of moles (n) = 1.46 g / 36.46 g/mol
Volume in liters (V) = n / M
V = n / M = (1.46 g / 36.46 g/mol) / 0.1 M
Now, plug in the values and calculate:
V = (0.04 mol) / 0.1 M
V = 0.4 L
Therefore, the volume of a 0.1 M HCl solution containing 1.46 g of HCl is 0.4 liters.
To find the volume of the 0.1 M HCl solution, we can use the equation:
Molarity (M) = moles (n) / volume (V)
First, let's calculate the number of moles of HCl in the given mass of 1.46 g:
moles (n) = mass (m) / molar mass (M)
The molar mass of HCl is the sum of the atomic masses of hydrogen (H) and chlorine (Cl), which can be found on the periodic table. It is approximately 1 g/mol for hydrogen and 35.5 g/mol for chlorine.
Molar mass (M) = 1 g/mol (hydrogen) + 35.5 g/mol (chlorine) = 36.5 g/mol
Now we can calculate the number of moles of HCl:
moles (n) = 1.46 g / 36.5 g/mol ≈ 0.04 mol
Next, we'll use the formula for molarity to find the volume (V) of the solution:
Molarity (M) = moles (n) / volume (V)
Rearranging the formula to solve for volume:
Volume (V) = moles (n) / molarity (M)
Substituting the values into the equation:
Volume (V) = 0.04 mol / 0.1 mol/L = 0.4 L
So, the volume of the 0.1 M HCl solution containing 1.46 grams of HCl is approximately 0.4 liters.