the density of liquidwater is 0.997g/mlat 25 degree Calculate the massof 250ml of water
The given density of liquid water is 0.997 g/ml.
We need to find the mass of 250 ml of water.
We can use the formula:
mass = density x volume
Substituting the given values, we get:
mass = 0.997 g/ml x 250 ml
mass = 249.25 g
Therefore, the mass of 250 ml of water is 249.25 g.
how many moles of water are in 250mml of water
To calculate the number of moles of water in 250 mL of water, we need to use the formula:
moles = mass / molar mass
We already calculated the mass of 250 mL of water in the previous question, which is 249.25 g.
The molar mass of water (H2O) is 18.015 g/mol.
Now, we can calculate the number of moles:
moles = 249.25 g / 18.015 g/mol
moles = 13.83 mol
Therefore, there are 13.83 moles of water in 250 mL of water.
Calculate the volume that would be occupied by two. By 2. 000 moles of water at 25 degree Celsius.
To calculate the volume of 2.000 moles of water at 25°C, we need to use the ideal gas law:
PV = nRT
where P is the pressure of the gas, V is the volume, n is the number of moles of the gas, R is the gas constant, and T is the temperature in Kelvin.
At 25°C, the temperature in Kelvin is:
T = 25°C + 273.15 = 298.15 K
The pressure of the gas is not given, so we will assume standard pressure (1 atmosphere or 101.325 kPa).
The gas constant is:
R = 0.0821 L·atm/(mol·K)
Substituting the given values and solving for V:
V = (nRT) / P
V = (2.000 mol x 0.0821 L·atm/(mol·K) x 298.15 K) / 101.325 kPa
V = 47.2 L
Therefore, 2.000 moles of water at 25°C would occupy a volume of approximately 47.2 liters.
All chemists weighs are steel cylinder of compressed oxygen O2 and find that it has masss of 1027.8 grams. After some of the oxygen is used in an experiment, cylinder has a mass of 1023.2 grams. How many moles of oxygen gas are used in the experiment.
First, we need to find the mass difference of the oxygen gas that was used in the experiment.
Mass difference = initial mass - final mass
Mass difference = (1027.8 g) - (1023.2 g)
Mass difference = 4.6 g
Next, we can use the molar mass of oxygen gas to calculate the number of moles that corresponds to this mass difference. The molar mass of O2 is 32.00 g/mol.
moles of O2 = mass difference / molar mass
moles of O2 = 4.6 g / 32.00 g/mol
moles of O2 = 0.14375 mol
Therefore, 0.14375 moles of O2 were used in the experiment.
Calculate Number of atoms in 0.0082 gram of gold.
To calculate the number of atoms in 0.0082 grams of gold, we need to use the following steps:
1. Find the molar mass of gold (Au). The molar mass of Au is 196.97 g/mol.
2. Convert the given mass of gold from grams to moles by dividing by the molar mass:
moles of Au = 0.0082 g / 196.97 g/mol = 4.167 × 10^-5 mol
3. Use Avogadro's number (6.022 × 10^23 atoms/mol) to calculate the number of atoms:
number of atoms = moles of Au x Avogadro's number
number of atoms = 4.167 × 10^-5 mol x 6.022 × 10^23 atoms/mol
number of atoms = 2.506 × 10^19 atoms
Therefore, there are 2.506 × 10^19 atoms in 0.0082 grams of gold.
To calculate the mass of 250 mL of water, we will use the given density of liquid water, which is 0.997 g/mL.
The formula to calculate the mass is:
Mass = Volume × Density
Let's substitute the given values into the formula:
Mass = 250 mL × 0.997 g/mL
Now, we can calculate the mass:
Mass = 249.25 g
Therefore, the mass of 250 mL of water is 249.25 grams.