Simplify 100110+11011 in binary numeral
The given binary numerals are:
100110
+ 11011
-------
111001
Therefore, the simplified binary numeral is 111001.
Work out in base twelve: TTE+T0E
In base twelve, T represents ten and E represents eleven. We can rewrite the given addition problem as:
(10)(12)^2 + (10)(12)^1 + (11)(12)^0
+ (10)(12)^2 + (0)(12)^1 + (11)(12)^0
Simplifying this expression, we get:
(10)(144) + (10)(12) + (11)(1)
+ (10)(144) + (0)(12) + (11)(1)
= 1440 + 120 + 22 + 1440 + 0 + 11
= 3083
Therefore, TTE + T0E = 3083 in base twelve.
To simplify the expression 100110 + 11011 in binary numeral, we perform binary addition.
Let's align the numbers:
100110
+ 11011
-----------
We start from the rightmost column and add the corresponding bits:
0 <- carry (no carry in the rightmost column)
+ 0
-----------
0
Next column:
1 <- carry
+ 1
-----------
10
Next column:
0 <- carry
+ 1
-----------
01
Next column:
0 <- carry
+ 1
-----------
01
Next column:
1 <- carry
+ 1
-----------
100
The result when we combine the carried digits:
100110
+ 11011
-----------
110001
Therefore, 100110 + 11011 in binary numeral is equal to 110001.