The letters for the word math are placed in a bag. Two letters are selected with replacement. Which statements are true about the tree diagram that could represent the possible outcomes?? Select all that apply.
A. There would be 4 tree bases.
B. Each base would have 3 tree branches.
C. The diagram would show a total of 12 possible outcomes.
D. There would be 4 combinations that have double letters.
A. There would be 4 tree bases.
B. Each base would have 3 tree branches.
C. The diagram would show a total of 16 possible outcomes.
The letters for the word math are placed in a bag. Two letters are selected with replacement. Which statements are true about the tree diagram that could represent the possible outcomes? Select all that apply. Only can chose 2
A. There would be 4 tree bases.
B. Each base would have 3 tree branches.
C. The diagram would show a total of 12 possible outcomes.
D. There would be 4 combinations that have double letters.
A. There would be 4 tree bases.
B. Each base would have 4 tree branches.
A spinner has three equal sections labeled 1, 2, and 3.
Which organized list shows the possible outcomes for spinning the spinner twice?
A.
1,1; 1,2; 1,3
2,1; 2,2; 2,3
3,1; 3,2; 3,3
B.
1,2; 1,3
2,1; 2,3
3,1; 3,2
C.
1,1; 1,2; 1,3
2,2; 2,3
3,3
D.
1,1; 1,2; 1,3
A.
1,1; 1,2; 1,3
2,1; 2,2; 2,3
3,1; 3,2; 3,3
A spinner has three equal sections labeled 1, 2, and 3.
What is the probability of getting two numbers that have a sum of 5 on the spinner?
A. two-ninths
B. one-third
C. one-sixth
D. four-ninths
4 / 4
3 of 4 Answered
B. one-third
The only way to get a sum of 5 is to spin a 2 and a 3, or to spin a 3 and a 2. The probability of spinning a 2 is 1/3 and the probability of spinning a 3 is 1/3. Since the spins are independent, the probability of getting both a 2 and a 3 is (1/3) × (1/3) = 1/9. But there are two possible ways to get a sum of 5, so the total probability is 2/9, which simplifies to one-third.
A bag contains 4 white, 3 blue, and 5 red marbles.
Find the probability of choosing a red marble, then a white marble if the marbles are replaced.
A. one-twelfth
B. five over thirty-six
C. five-sixths
D. five-twelfths
D. five-twelfths
The probability of choosing a red marble on the first draw is 5/12 because there are 5 red marbles out of a total of 12 marbles. Since the marble is replaced before the second draw, the probabilities are the same for the second draw. The probability of choosing a white marble on the second draw is 4/12, or 1/3, because there are 4 white marbles remaining out of a total of 12 marbles. To find the probability of both events happening, we multiply the probabilities: (5/12) × (1/3) = 5/36. But the question asks for the probability of first choosing a red marble, then choosing a white marble. Since the marble is replaced after the first draw, these events are independent, so we can multiply the probabilities again: (5/12) × (4/12) = 20/144, which simplifies to 5/36.
A bag contains 4 white, 3 blue, and 5 red marbles.
Find the probability of choosing 3 blue marbles in a row if the marbles are replaced.
A. two over eleven
B. one over two hundred twenty
C. Fraction 1 over 27 end fraction
D. one over sixty-four