number of atoms in 3.227*10^10 mol of potassium
There are 1.948 x 10^29 atoms in 3.227 x 10^10 mol of potassium.
To calculate this:
1. Start with Avogadro's constant, which is the number of atoms in one mole of a substance: 6.022 x 10^23 atoms/mol.
2. Multiply Avogadro's constant by the number of moles of potassium:
6.022 x 10^23 atoms/mol * 3.227 x 10^10 mol = 1.948 x 10^29 atoms
To determine the number of atoms in a given amount of substance, you can use Avogadro's number, which is approximately 6.022 * 10^23 atoms/mol.
First, convert the given amount of substance from moles to atoms using Avogadro's number:
Number of atoms = (Number of moles) * (Avogadro's number)
Number of atoms = (3.227 * 10^10 mol) * (6.022 * 10^23 atoms/mol)
Number of atoms = 1.944 * 10^34 atoms
Therefore, there are approximately 1.944 * 10^34 atoms in 3.227 * 10^10 mol of potassium.