In circle O, M<AOB = 118, and M<BOC = 126.
What is mAC
Since the angles in a triangle always add up to 180 degrees, we can find M<BOA by subtracting the other two angles from 180:
M<BOA = 180 - 118 - 126 = 64
Now, since AC is a diameter (which means it passes through the center of the circle O), we know that M<BOA + M<BOC = 180. Plugging in values, we get:
64 + 126 = 180
Simplifying, we get:
M<ACB = 180 - 64 - 126 = 10
Therefore, mAC = M<ACB + M<ABC = 10 + (118/2) = 10 + 59 = 69 degrees.
To find the measure of angle mAC, we need some additional information about the circle O. Specifically, we need to know the relationship between angles AOB, BOC, and AC.
Please provide any additional details or information about the circle O.