what is the value of a resistor that transform 2.0 mA of current when it is connected to a 6.0-V battery
We can use Ohm's Law to solve this problem. Ohm's Law states that the voltage (V) across a resistor is equal to the current (I) passing through it multiplied by its resistance (R):
V = I × R
We are given that the current passing through the resistor is 2.0 mA and the voltage across it is 6.0 V, so we can rearrange Ohm's Law to solve for the resistance:
R = V / I
R = 6.0 V / 2.0 mA
Note that we must convert the current from milliamperes (mA) to amperes (A) before performing the calculation. 1 mA is equal to 0.001 A, so:
R = 6.0 V / 0.002 A
R = 3000 Ω
Therefore, the resistance of the resistor is 3000 Ω (or 3 kΩ).
To find the value of the resistor, we can use Ohm's Law, which states that the voltage across a resistor (V) is equal to the current (I) multiplied by the resistance (R): V = I * R.
Given:
Current (I) = 2.0 mA = 2.0 * 10^-3 A
Battery voltage (V) = 6.0 V
Rearranging Ohm's Law, we get R = V / I.
Substituting the given values, we have:
R = 6.0 V / 2.0 * 10^-3 A
Calculating:
R = 6.0 V / 0.002 A
R = 3000 Ω (ohms)
Therefore, the value of the resistor that can transform 2.0 mA of current when connected to a 6.0-V battery is 3000 ohms.