Evaluate ฯƒ๐‘Ÿ=1

16 (5๐‘Ÿ โˆ’ 1)

There are a couple of ways to approach this evaluation, but one common method is to use the formula for the sum of an arithmetic series:

Sn = n/2(a1 + an)

where Sn is the sum of the first n terms, a1 is the first term, an is the nth term, and n is the number of terms.

In this case, we are summing the expression 16(5r - 1) from r = 1 to r = n. So we can plug in a1 = 16(5(1) - 1) = 64, an = 16(5n - 1), and n = 1:

S1 = 1/2(64 + 16(5(1) - 1)) = 40

Therefore, ฯƒ๐‘Ÿ=1 16(5๐‘Ÿ โˆ’ 1) = 40.

To evaluate the expression ฯƒ๐‘Ÿ=1 16 (5๐‘Ÿ โˆ’ 1), we will substitute different values of ๐‘Ÿ and calculate the result for each value.

Let's start by substituting ๐‘Ÿ = 1 into the expression:

ฯƒ1=1 16 (5(1) โˆ’ 1)
= 16 (5 - 1)
= 16 (4)
= 64

Therefore, when ๐‘Ÿ = 1, the expression evaluates to 64.