A gas sample has a volume of 0.150 L at a temperature of 265K. what volume will the gas occupy at 288 K?
(V1/T1 = V2/T2)
a
138 L
b
13.8 L
c
0.163 L
d
163 L
Using the formula V1/T1 = V2/T2, we can solve for V2:
V1/T1 = V2/T2
V2 = V1(T2/T1)
V2 = 0.150 L (288 K/265 K)
V2 = 0.163 L
Therefore, the gas will occupy a volume of 0.163 L at 288 K. The answer is (c).
To find the volume that the gas will occupy at 288K, we can use the formula V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.
Given:
V1 = 0.150 L
T1 = 265 K
T2 = 288 K
Plugging these values into the formula:
V1/T1 = V2/T2
(0.150 L) / (265 K) = V2 / (288 K)
Cross-multiplying:
(0.150 L) * (288 K) = (265 K) * V2
43.2 L*K = 265 K * V2
Now, divide both sides of the equation by 265 K to solve for V2:
43.2 L*K / 265 K = V2
V2 ≈ 0.163 L
Therefore, the gas will occupy approximately 0.163 L at 288 K.
The correct answer is option c) 0.163 L.