How many ways can 7 basketball players be listed in order in a program.
There are 7 choices for the first player, 6 choices for the second player (since one has already been chosen), 5 choices for the third player, and so on, down to 1 choice for the seventh player. So the total number of ways is:
7 × 6 × 5 × 4 × 3 × 2 × 1 = 5040
Therefore, there are 5040 ways to list 7 basketball players in order in a program.
To determine the number of ways 7 basketball players can be listed in order, we can use the concept of permutations.
The formula for permutations is:
P(n,r) = n! / (n-r)!
where n is the total number of items and r is the number of items selected.
In this case, we need to find the number of ways 7 players can be listed, so n = 7 and r = 7.
Plugging these values into the formula, we get:
P(7,7) = 7! / (7-7)!
= 7! / 0!
Since the factorial of 0 (0!) is defined as 1, the equation simplifies to:
P(7,7) = 7! / 1
= 7!
Evaluating 7!, we find:
7! = 7 x 6 x 5 x 4 x 3 x 2 x 1
= 5040
Therefore, there are 5040 ways that 7 basketball players can be listed in order in a program.