In Young's double slit experiment, the slit are separated by 0.28mm and the screen is placed 1.4m away . the distance between the central bright fringes is measured to be 1.2cm .determine the wavelength of light used in the experiment?
We can use the formula:
λ = (d * y) / D
where λ is the wavelength of light, d is the distance between the slit (0.28mm), y is the distance between the central bright fringe and the first bright fringe on either side (0.6cm or 0.006m), and D is the distance between the slit and the screen (1.4m).
Plugging in the values, we get:
λ = (0.28 * 0.006) / 1.4
= 0.0000012 m or 1.2 x 10^-6 m
Therefore, the wavelength of light used in the experiment is 1.2 x 10^-6 meters or 1200 nanometers.
To determine the wavelength of light used in Young's double slit experiment, we can use the formula:
λ = (d * L) / D
Where:
λ = wavelength of light
d = separation between the slits (0.28 mm = 0.28 * 10^(-3) m)
L = distance from the slits to the screen (1.4 m)
D = distance between adjacent bright fringes (1.2 cm = 1.2 * 10^(-2) m)
Substituting the given values into the formula:
λ = (0.28 * 10^(-3) * 1.4) / (1.2 * 10^(-2))
Simplifying the expression:
λ = 0.0392 m
Therefore, the wavelength of light used in the experiment is 0.0392 meters.