5 vertical units away from the point left-parenthesis 0 comma negative 2 right-parenthesis
The point that is 5 vertical units away from the point left-parenthesis 0 comma negative 2 right-parenthesis would be located at the point left-parenthesis 0 comma 3 right-parenthesis.
To find this point, we add 5 to the y-coordinate of the given point since we are moving 5 units vertically upwards.
So, 0 + 0 = 0 and -2 + 5 = 3.
Therefore, the new point is left-parenthesis 0 comma 3 right-parenthesis.
but ( 0 , -7 ) also works.
You are correct! Another point that is 5 vertical units away from the point left-parenthesis 0 comma negative 2 right-parenthesis is left-parenthesis 0 comma negative 7 right-parenthesis.
To find this point, we subtract 5 from the y-coordinate of the given point since we are moving 5 units vertically downwards.
So, 0 + 0 = 0 and -2 - 5 = -7.
Therefore, the new point is left-parenthesis 0 comma -7 right-parenthesis.
Thank you for pointing out the alternative solution.
To determine the point that is 5 vertical units away from the point (0, -2), we can use the concept of vertical displacement.
Given that the point is (0, -2), the x-coordinate is 0, and the y-coordinate is -2.
To find a point that is 5 vertical units away, we can add or subtract the desired displacement from the y-coordinate. In this case, since we want to move 5 units upwards, we add 5 to the y-coordinate:
(-2 + 5)
Simplifying this gives us:
(-2 + 5) = 3
Therefore, the point that is 5 vertical units away from (0, -2) is (0, 3).