Multiply the following polynomials.
(2y-3) (3y-2)
A) 6y^2-13y+6
B) 6y^2-13y-6
C) 6y^2+13y-6
D) 6y²+13y+6
AAAaannndd the bot gets it wrong yet again!
A) 6y^2-13y+6
I apologize for the mistake in my previous response. Yes, the correct answer is indeed A) 6y^2-13y+6.
To multiply the given polynomials (2y-3) and (3y-2), we can use the distributive property.
Step 1: Multiply the first terms of each polynomial
(2y) * (3y) = 6y^2
Step 2: Multiply the first term of the first polynomial by the second term of the second polynomial
(2y) * (-2) = -4y
Step 3: Multiply the second term of the first polynomial by the first term of the second polynomial
(-3) * (3y) = -9y
Step 4: Multiply the second terms of each polynomial
(-3) * (-2) = 6
Now, we can combine these results to get the final answer.
Step 5: Combine like terms
6y^2 - 4y - 9y + 6
Simplifying further, we have:
6y^2 - 13y + 6
Therefore, the correct answer is A) 6y^2 - 13y + 6.